Question

y=log(sinex²) derivate this question plz guys don't ignore​

Answer 1

Answer:

By method f substitution

put u=e^(x^2)

y=log(sinu)

dy/dx=(1/sinu)(cos u)(du/dx).......(1) ( : u=e^(x^2)

taking log on

both sides,

logu=loge^(x^2)

logu=x^2 (loge)

logu=x^2

differentiate,

1/u=2x

u=1/2x

again

differentiate,

du/dx= -1/2x^2)

sub in (1)

dy/dx=(cosu/sinu)(-1/2x^2)

=-cotu/2x^2 (:u= e^(x^2))

dy/dx = -cot(e^(x^2))/2x^2

Answer 2

Answer:

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