y=log x base 2.
find dy/dx.
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when y = ln(x) , dy/dx = 1/x , { remember , here base = e }
when y = log x base a, dy/dx = 1/x(ln a)
, on solving answer would be
1/x(ln2)
Answered by
7
hey friend here is your answer...
hope it helps you☺️☺️✌️✌️
hope it helps you☺️☺️✌️✌️
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Debojyotidev:
thnks a lot friend
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