Math, asked by khushi369sharma, 5 months ago

y= log (x³+1)³ find dy/dx

Answers

Answered by anku3842

0

Answer:

y'=−1xln3(log3x)2. Explanation: y=log x3=1log3x=(log3x)−1. y'=−(log3x)−2⋅1xln3. y'=−1x ln3(log3x)2.

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