Question

Y=log7(log7x) find dy by dx

Answer 1

Step-by-step explanation:

Let y = log7(log7x)

differentiating both sides w.r.t. x

dy/dx = d/dx (log7(log7x))

Using 'u.v' rule

dy/dx = log7.d/dx(log7x) + log7x.d/dx(log7)

dy/dx = log7×1/7x×7 + log7x1/7×0

dy/dx = xlog7