Question

y=logx then find the value of d^2y/dx^2​

Answer 1

Answer:

Answer :

$y = log(x)$

$\frac{dy}{dx} = \frac{1}{x} \times 1$

$\frac{dy}{dx } = \frac{1}{x}$

$\frac{ {dy}^{2} }{ {dx}^{2} } = \frac{1}{1} = 1$

$answer \: will \: be \: 1$