Question

)
y = sec [ 1+tan x] find dy/dx​

Answer 1

$y = sec(1 + tanx) \\ \frac{dy}{dx} = \frac{d}{dx} sec(1 + tanx) \\ = sec(1 + tanx)tan(1 + tan) \frac{d}{dx} (1 + tanx) \\ = sec(1 + tanx)tan(1 + tanx) {sec}^{2} x$