Question

Y=sin^-1(3x-4x^3) then dy÷dx =?

Answer 1

Answer:

solved

Step-by-step explanation:

Y=sin^-1(3x-4x³)

3x-4x³ = siny

siny = 3x-4x³

y' cosy = 3 - 12x²

y' = (3 - 12x²) /cosy

y' = (3 - 12x²) /√1 - sin²y

y' = (3 - 12x²) /√{1 - ( 3x-4x³ )²}