Question

y=sin(1+x2/1-x2)then dy/dx​

Answer 1

Answer:

cos(1+x^2/1-x^2)*[{2x(1-x^2) + 2x(1+x^2)}/(1-x^2)^2]

Step-by-step explanation:

y=sin(1+x2/1-x2)

We know that derivative of sinx is cosx then

dy/dx = cos(1+x2/1-x2)

but this is not complete yet as we have to differentiate the theta

then use chain rule and quotient rule for the same

we get

dy/dx = cos(1+x^2/1-x^2)*[{2x(1-x^2) + 2x(1+x^2)}/(1-x^2)^2]

hence the result