Question

y= sin^2x^2-cos^2x^2​

Answer 1

Answer: Get the lube out of your hand

Step-by-step explanation:

Answer 2

Let y = sin²x² - cos²x²

Differentiating w.r.t. x, we get

dy d

dx dx

[sin² x² - cos²x²]

d dx = d (sin 2²)²-(cos r²) ² 2 dx

d = 2sin x² (sin x²) – 2cos x². dx d dx -(cos x²)

=

d 2sin 2². cos 2² (2²) . dx (x²) - 2 cos x2. (- sin x2). d dx

= 2sin x2 cos x2 x 2x + 2sinx2 cosx2x2x

= 4x (2sinx2cosx

= 4x sin(2x²).