Math, asked by anjaliwankhede, 1 year ago

y=sin(3x+5) show that d2y/dx^2+9y=0

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Answered by AnkitNobi

0

y = sin(3x+5) then dy/dx = 3cos( 3x+5)
d2y/dx^2 = -9sin(3x+5) so d2y/dx^2 = -9y
d2y/ dx^2 +9y = 0

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