Math, asked by 123147, 1 year ago

y= sin (a tan-1 x) find dy/dx

Answers

Answered by Anonymous
2
Hey!!!

Here is your answer_______

y = sin (a tan-1 x)

differentiate y with respect to x

dy/dx = cos (a tan-1 x) d/dx(a tan-1 x)

dy/dx = cos(a tan-1 x).a 1/(1+x^2)


hence,

dy/dx = a cos (a tan-1 x)/(1+x^2)


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Hope this answer will help u....
Answered by khushu18
0
your answer iss here ....
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