y= sin (a tan-1 x) find dy/dx
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Hey!!!
Here is your answer_______
y = sin (a tan-1 x)
differentiate y with respect to x
dy/dx = cos (a tan-1 x) d/dx(a tan-1 x)
dy/dx = cos(a tan-1 x).a 1/(1+x^2)
hence,
dy/dx = a cos (a tan-1 x)/(1+x^2)
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Hope this answer will help u....
Here is your answer_______
y = sin (a tan-1 x)
differentiate y with respect to x
dy/dx = cos (a tan-1 x) d/dx(a tan-1 x)
dy/dx = cos(a tan-1 x).a 1/(1+x^2)
hence,
dy/dx = a cos (a tan-1 x)/(1+x^2)
=========================
Hope this answer will help u....
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