Question

y=sin²(ax+b) find Dy/dx

Answer 1

Answer:

dy/dx=d/dx[sin²(ax+b)]

dy/DX=2sin(ax+b)[d/DX sin(ax+b)] ....(chain rule)

dy/DX=2sin(ax+b)cos(ax+b)

=> dy/DX=sin2(ax+b)