y sq = 4 ax and the line y =2 a and y axis find the area under the curve
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Integral 0 to 2a yv2/4a
=1/4a(yv3/3)between the limits 0 to 2a
=1/4a(8av3/3) =2av2/3
=1/4a(yv3/3)between the limits 0 to 2a
=1/4a(8av3/3) =2av2/3
prabh34444:
yr tell me that queston which i newly posted
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solutio n of these sum
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