Question

y square +1/3y =2 using by formula​

Answer 1

Answer:

y² + 1/3 y = 2

first of all resolve it in general form ay² + by + c = 0 .

e.g., y² + 1/3 y = 2

=> 3y² + y = 2 × 3

=> 3y² + y - 6 = 0

if ay² + by + c = 0

then, y = {-b ± √(b² - 4ac)}/2a use it here,

3y² + y - 6 = 0

so, y = {-1 ± √(1² - 4.3(-6))}/2(3)

= {-1 ± √(1 + 72)}/6

= (-1 ± √73)/6

hence, roots are (-1 + √73)/6 and (-1 - √73)/6

Explanation: