Math, asked by and57, 1 year ago

y=tan^–1(x/√1-x²) please help

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Answered by shashankavsthi
2

take \: x =  \sin( \alpha )  \\ then \\ arctan \frac{ \sin( \alpha ) }{ \sqrt{1 -  { (\sin( \alpha )) }^{2} } }  \\ arctan( \frac{ \sin( \alpha ) }{ \cos( \alpha ) } ) \\  \\ arctan(tan \alpha ) \\  =  \alpha  \\  \alpha  = arcsinx
hope this will help you.
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