Question

y = tan(logx) find dy/dx
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Answer 1

Step-by-step explanation:

We have,

$y = \tan( log(x) )$

Differentiating both sides w.r.t x, we get,

$\frac{dy}{dx} = \frac{1}{1 + {( log(x)) }^{2} } . \frac{1}{x}$

$\implies\frac{dy}{dx} = \frac{1}{x+ x{( log(x)) }^{2} }$