y varies directly as square of x'. When y = 10 then x = 4. Find the value of x when y = 35.
(a) 2.5
(b) 6
(c) -2.5
(d) -7.4
Answers
Answered by
1
Answer:
6 is your answer
Step-by-step explanation:
6 is your answer
Answered by
1
Step-by-step explanation:
- So the question is y varies directly as the square of x. So we get
- So y ά x^2
- Let y = kx^2 (k is a variation constant)
- So y = 10 when x = 4, substituting the same we get
- 10 = k (4)^2
- 16 k = 10
- So k = 10/16
- Or k = 5/8
- So substituting we get the equation as
- So y = 5/8 x^2
- Now putting y = 35 we get
- 35 = 5/8 x^2Ѵ
- So 5/8 x^2 = 35
- Or x^2 = 35 x 8 / 5
- Or x^2 = 56
- Or x = sq root 56
- Or x = 7.48
Reference link will be
https://brainly.in/question/23075220
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