Math, asked by param573830, 8 months ago

y varies directly as square of x'. When y = 10 then x = 4. Find the value of x when y = 35.
(a) 2.5
(b) 6
(c) -2.5
(d) -7.4​

Answers

Answered by Charityadav
1

Answer:

6 is your answer

Step-by-step explanation:

6 is your answer

Answered by knjroopa
1

Step-by-step explanation:

  • So the question is  y varies directly as the square of x. So we get
  •           So y ά x^2
  •        Let y = kx^2 (k is a variation constant)
  •        So y = 10 when x = 4, substituting the same we get
  •               10 = k (4)^2
  •                16 k = 10
  •             So k = 10/16
  •                Or k = 5/8
  • So substituting we get the equation as
  •          So y = 5/8 x^2
  • Now putting y = 35 we get
  •              35 = 5/8 x^2Ѵ
  •            So 5/8 x^2 = 35
  •              Or x^2 = 35 x 8 / 5
  •               Or x^2 = 56
  •                  Or x = sq root 56
  •                  Or x = 7.48

Reference link will be

https://brainly.in/question/23075220

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