Question

y=(x-1)/(x+1) find dy/dx

Please tell the solution or atleast the final answer... Please write the correct answer and if you don't just leave don't make me angry by your answer...

Answer 1

Explanation:

$y = \frac{(x - 1)}{(x + 1)} \\ \frac{dy}{dx} = \frac{(x + 1) \frac{d}{dx}(x - 1) - (x - 1) \frac{d}{dx} (x + 1) }{( {x + 1)}^{2} } \\ = \frac{(x + 1) \times (1) - (x - 1) \times (1)}{ {(x + 1)}^{2} } \\ = \frac{(x + 1 - x + 1)}{ {(x + 1)}^{2} } \\ = \frac{ 1 + 1}{( {x + 1)}^{2} } \\ = \frac{2}{( {x + 1)}^{2} }$