Question

y=√x + 1/√x)^2. Differentiate (dy/dy).

It's Urgent​

Answer 1

Answer:

1

Step-by-step explanation:

y=√x + 1/√x)^2. Differentiate (dy/dy).

=1

Answer 2

Hie!!

Given Question is y = { √x + 1/√x }²

y = { (√x)² + (1/√x)² + 2(√x) (1/√x) }

Becoz ( a + b )² = a² + b² + 2ab

y = x + 1/x + 2

Now, Differentiate both sides w.r.t x we have.

dy/dx = 1 - 1/x²

Note:-

Differentiation of 1/x or x-¹ w.r.t x is

-1( x-² ) = -1/x²

Becoz Differentiation of xⁿ w.r.t x is

nxⁿ-¹

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If The questions is like this find dy/dy

Then

y = x + 1/x + 2

y = y

Now, Differentiate both sides w.r.t. y we have

dy/dy = 1