Question

y = x⅓ - x^-⅓ then y^3+3y
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Answer 1

Step-by-step explanation:

x^1/3+y^1/3 = z^1/3 , cubing on both sides

x +y +3x⅓ y⅓ (x⅓ +y⅓ ) = z

substitute x⅓ +y⅓ = z⅓

x+y+ 3 x⅓y⅓ ( z⅓ ) = z

(x+y-z) = - 3 x⅓ y⅓ z⅓

Again cubing

(x+y-z) ³ = -27 xyz

(x+y-z) ³ + 27 xyz =0

hope this helps you...plz Mark as BRAINLIEST answer❤