Question

y=x³-6x²+9x-5.find f'(x) and y at its minima and maxima.​

Answer 1

Answer:

The value of f'(x) is 3(x-3)(x-1)

Step-by-step explanation:

y = f(x) = x^3 - 6x^2 + 9x - 5

f'(x) = 3x^2 - 12x + 9

f'(x) = 3(x^2 - 4x + 3)

= 3(x-3)(x-1)

Substituting x=3 in f(x)

f(3) = -5

Substituting x=1 in f(x)

f(1) = -1

Since f(1) > f(3)

x=1 is a point of maxima ans

x=3 is a point of minima

Answer 2

Step-by-step explanation:

See the solution.

Hope it helps!