Math, asked by simmi1457, 9 months ago

Y²+1=0
find the value of y=?

Answers

Answered by OPRS
2

hello mate.....!!!

given.....

y {}^{2}  + 1 = 0 \\  \\ y {}^{2}  =  - 1 \\  \\ y {}^{2}  = i {}^{2} 1 {}^{2}  \\  \\

we know 》

i {}^{2}  =  - 1 \: \:  \\ and \: \:  \:  \:  \:  1 {}^{2}  = 1

then》

y =  \sqrt{i {}^{2} } 1 {}^{2}  \\  \\ y =  \sqrt({1i) {}^{2} }  \\  \\ y = 1i

Hope it helps you....!!!

Answered by yushanaqvi70
0

Step-by-step explanation:

hope i5 helps u byeeeee

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