Question

Y³-27 bit i have this question why i ask new question

Answer 1

Answer:

${y}^{3} - 27 = {y}^{3} - {3}^{3} \\ {y}^{3} - {3}^{3} = {(y - 3)}^{3} + 3 \times y \times 3(y - 3) \\ {y}^{3} - {3}^{3} = {(y - 3)}^{3} + {9y}^{2} - 27y$

Step-by-step explanation:

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