y3-7 y+ 6
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1
Answer:
Step-by-step explanation:
y3-7 y+ 6
y-4 y+6
y+y=6+4
2y=10
y=10/2
y=5
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Answered by
0
Answer:
ANS:Let p(x) = y3 - 7y + 6 then,by trial and error method we find p(1) = 0
Therefore, (y - 1) is a factor of p(x).
By dividing p(x) by y-1 we get, y2+y - 6
=> y2 - 2y +3y -6
=> y(y - 2) +3(y - 2)
=> (y + 3)(y - 2)
Now, y3 - 7y + 6 can be written in the factorised form as (y - 1)(y + 3)(y - 2)
ANS: (y - 1)(y + 3)(y - 2)
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