Physics, asked by janvisingla17, 1 year ago

ya pls hlp me out pls ans this question

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Answered by rameshafernandosrtzc
1
Applying F=ma,

Force applied = 0.5 kg x 16 ms^-2 [using the first object]
                      = 80 N

Mass of the second object = 80 N / 4 ms^-2
                                           = 2 kg
∴Acceleration of the whole system = 80 N/(0.5 kg+2 kg)
                                                        = 3.2 ms^-2



janvisingla17: thanx
rameshafernandosrtzc: Anytime! :D
janvisingla17: okk
janvisingla17: 0.5×16 is 8 so why u written as 80
janvisingla17: pls tell
rameshafernandosrtzc: Oh sry dr! It's a mistake. Thu sum is correct but you have to replace 8 for 80.
janvisingla17: no problem at all
Answered by chiefLucky
1
F=ma=0.5*16=8 N
F=ma
8=m*4
m=2 kg
Total mass=2+0.5=2.5 kg
Force = 8N
F=ma
8=2.5*a
a=8/2.5=8*10/25=80/25=3.2 m/s2
Pls mark as brainliest :-)

janvisingla17: thnx
chiefLucky: No prob :-(
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