Question

yadi 15 cotA =8 ho to sinA or secA ka man koi bata do please argent hai

Answer 1

15CotA = 8


CotA = 8/15 = B/P



B = 8 and P = 15



By Pythagoras theroem ,


( H )² = (B)² + (P)²


( H )² = (8)² + (15)²


H² = √289

H = 17


Therefore,

SinA = P/H = 15/17

And,


SeCA = H/B = 17/8

Answer 2

Hello!

$\bf{15 \: cotA = 8}$

Given,
cotA = $\dfrac{8}{15} = \dfrac{\sf B}{\sf P}$

$\star \: \sf B = 8$
$\star \: \sf P = 15$

Then,

$\sf H^{2} = \sf B^{2} + P^{2} \\ \\ \implies \sf H^{2} = (8)^{2} + (15)^{2} \\ \\ \implies \sf H^{2} = 64 + 225 \\ \\ \implies \sf H = \sqrt {289} \implies \boxed{\blue{\bf{H = 17}}}$

Therefore,

♦ $\sf sinA = \dfrac{\sf P}{\sf H} = \boxed{\red{\bf{\dfrac{15}{17}}}}$

♦ $\sf secA = \dfrac{\sf H}{\sf B} = \boxed{\red{\bf{\dfrac{17}{8}}}}$

Cheers!