Question

yadi sina=4/3 aur sinb=5/13 hai to sin(a-b)= ​

Answer 1

SinA=4/5 , cotA= 3/4

sinB=5/13 , cotB=12/5

cot(A-B)=( cotA.cotB + 1)/(cotB - cotA)

=( 3/4×12/5 + 1)/(12/5 - 3/4)

=(9/5 + 1)/(48-15/20)

=(9+5)5/(33/20)

=14×4/33

=56/33