Question

yash scored 40 marks in a test getting 3 marks for each right answer and losing 1 marks for each wrong answer many years would have score 50 marks how many questions were there in a test

Answer 1

hey there !!

Let correct question = x

And incorrect question  = y

Yash scored 40 marks in a test, getting 3marks for each right answer and losing1 mark for each wrong answer.

3x -  y = 40

Subtract 3x both sides we get

-Y = 40 – 3x        

Change the sign we get

Y = 3x – 40 …(1)

Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks

We get

4x – 2y = 50

Plug the value of y we get

4x – 2(3x - 40) =50

4x – 6x + 80 = 50

-2x = - 30

X = 15

Plug this value back in equation first we get

Y = 3x – 40

Y = 3* 15- 40

Y = 45 – 40

Y = 5

hope it helps !!!

Answer 2

Here is your solution

Let

correct question = x

incorrect question  = y

Yash scored 40 marks in a test, getting 3marks for each right answer and losing1 mark for each wrong answer.

Equation here ⬇⬇

3x -  y = 40

On Subtracting  3x both sides we get:-

-Y = 40 – 3x        

Y = 3x – 40 ...................…(1)

Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks

Equation here ⬇⬇

4x – 2y = 50................. (2)

Putting  the value of y in equation (2)

4x – 2y = 50

4x – 2(3x - 40) =50

4x – 6x + 80 = 50

-2x = - 30

X = 15

Putting the value of x in equation  (1)

Y = 3x – 40

Y = 3×15- 40

Y = 45 – 40

Y = 5

Hence,

Total number of questions = x +y = 15+5 = 20✔

Hope it helps