Question

यदि 4749 तथा 5601 और 7092 में से प्रत्येक को बड़ी से बड़ी संभावित संख्या d से विभाजित किया जाता है तो प्रत्येक बार शेषफल r बचता है तो dऔर r का मान क्या होगा

Answer 1

d = 213  & r = 63

Step-by-step explanation:

4749  = ad  + r

5601 =  bd  + r

7092  = cd + r

=> 7092 - 5601  = (c - b)d  

=> 1491 = (c - b)d  

7092 - 4749 = (c - a)d

=> 2343 = (c - a)d

5601 - 4749 = (b-a)d

=> 852 = (b-a)d

1491 = 3 * 7  * 71

2343 = 3 * 11 * 71

852 = 2 * 2 * 3 * 71

3 * 71 is Common Factor

Hence 3 * 71 = 213

d = 213

4749 = 22 * 213 + 63

5601 = 26 * 213 + 63

7092 = 33 * 213 + 63

r = 63

Learn more:

Three numbers 5920, 7976 and 10803 when divided by a three digit ...

https://brainly.in/question/9594864

How many numbers divide 2304 and 3888 leaving the same ...

https://brainly.in/question/11406689

The greatest integer which when dividing the integers 13511, 13903 ...

https://brainly.in/question/11612998