. यदि 6= [x + {x + (x+ ...)}], तो x का मान होगा
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It is forming an AP.
In which,
a=x
d=0
an=6
Now, an=a+(n-1)d
6 = x+(n-1)O
6-x= O
6=x
....,...... .............. ....... .... ...... .....
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