Question

यदि A,B और C त्रिभुज ABC के अंत कोण हो तो दिखाइये कि - sin{B+C\2}=cos A\2​

Answer 1

Step-by-step explanation:

A + B + C =

$\pi$

=> A/2 + B/2 + C/2 =

$\frac{\pi}{2}$

=> B/2 + C/2 =

$\frac{\pi}{2} - \frac{a}{2}$

=> Sin(B/2 +C/2) =

$\sin( \frac{\pi}{2} - \frac{a}{2} )$

= Cos(A/2)

Regards, Kshitij