यदि एक चक्रीय चतुर्भुज का बाह्य कोण 50° हो, तो उसका आंतरिक सम्मुख कोण कितना होगा?; ∠ABC + ∠ADC = 180°; ∠CBE = 50°; ∴ ∠ABC = 180° – 50° = 130°; ∴ ∠ADC = 180° – 130° = 50°
A. 130°
B. 40°
C. 50°
D. 90°
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In an equilateral triangle abc ad is perpendicular to bc then find a d square
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Sorry I didn't know this question
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