Question

यदि $^{n}C_8 = \,^{n}C_2$, तो $^{n}C_2$ ज्ञात कीजिए।

Answer 1

Answer:

Step-by-step explanation:

$nC_{8}$ = $nC_{2} = nC_{n-2}$

         8 = n - 2

         n = 10

         $nC_{2}$ = $10C_{2}$

            = $\frac{10*9}{1*2}$ = 45

Answer 2

हल-

दिया है

$\bf \: {}^{n} c_{8}$=$\bf \: {}^{n} c_{2}$

n = 8 + 2 = 10

तब,

$\bf \: {}^{n} c_{2}$= $\bf \: {}^{10} c_{2}$

$= \frac{10!}{2!(10 - 2)!} = \frac{10!}{2! \times 8!} \\ \\ \\ = \frac{10 \times 9 \times 8!}{2 \times 1 \times 8!} = 45$