यदि
![p(y) = 2 + y + 2y {}^{2} - y {}^{2} p(y) = 2 + y + 2y {}^{2} - y {}^{2}](https://tex.z-dn.net/?f=p%28y%29+%3D+2+%2B+y+%2B+2y+%7B%7D%5E%7B2%7D++-+y+%7B%7D%5E%7B2%7D+)
तो
![p(0) p(0)](https://tex.z-dn.net/?f=p%280%29)
और
![p(1) p(1)](https://tex.z-dn.net/?f=p%281%29)
में क्या संबंध है?
Answers
Answered by
1
Answer:
when we solve p(0) then ans becomes 2
and we take p(1) then ans will be 4
hence the relation between p(1) is double of p(0) .
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