Question

यदि वर्ग समीकरण 9x2-kx+16=0के मूल समान है तो kका मान ज्ञात कीजिए​

Answer 1

Answer:

k = 24

Step-by-step explanation:

(a ± b)² = a² ± 2ab + b²

9x² - kx + 16 = 0

(3x)² - kx + 4² = 0

kx = 2(3x)(4) = 24x

k = 24

Answer 2

Given : वर्ग समीकरण 9x²-kx+16=0 के मूल समान है

To Find :  kका मान

Solution:

ax² + bx + c = 0

मूल समान  => b² - 4ac = 0

ax² + bx + c = 0

9x²-kx+16=0

=> a = 9

    b = - k

    c = 16

b² - 4ac = 0

=> (-k)² - 4(9)(16) = 0

=> k² - 2².3².4² =0

=> k² - 24² = 0

=> (k + 24)(k - 24) = 0

=> k = -24 , k = 24

k = ± 24

kका मान ± 24

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