यदि x, y तथा z ऐसी वास्तविक संख्याएँ हो, ताकि (x - 3) ^{2} + (y - 4) ^{2} + (z - 5) ^{2} = 0 तो (x+y+z) का मान बताओ?
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Step-by-step explanation:
(x-3) ^2,( y-4) ^2,(z-5)^2 are positive so sum of positive no. can't be zero but in question it is give that its sum is zero for that each term should be zero
- (x-3)=0, (y-4)=0, (z-5)=0
- x=3, y=4, z=5
- x+y+z=12
I hope you understand
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