Question

yellow light of wavelenght 6000 A. produces fringe with 0.8mm what will be the fringe width. if wavelenght 7500A. and the separation between the slit is doubled

Answer 1

Answer:

WAVE OPTICS

Explanation:

★ FRINGE WIDTH ★

GIVEN ;

» wavelength (1) = 6000 Å

» wavelength (2) = 7500 Å

» d1 (slit width ) = d

» d2 (slit width) = 2d

» ß¹ = Fringe Width of Wavelength (1) = 0.8 MILLIMETERS

» ß² = Fringe Width of Wavelength (2) = ???

NOW ;

♥ BY USING FORMULA ;

$\frac{ \beta 1}{ \beta 2} = \frac{ \frac{wavelength(1)}{d1} }{ \frac{wavelength(2)}{d2} }$

★ ß1 / ß2 = (6000 Å / d ) / (7500 Å / 2d )

» 0.8 / ß2 = (6000 × 2 ) / 7500

» 0.8 / ß2 = 12,000 Å / 7500 Å

«★» ß2 = 0.8 / 1.6 = 0.5 mm

♠ ANSWER :- If slit width is DOUBLE then the original ; FRINGE WIDTH IS

0.5 MILLIMETERS OR 5 × 10-⁴ m.