Question

Yo brainliacs!!☺️✌️$<b>$
Got an interesting question for you all☺️✌️
A copper ball of density 8.6g/cc and 1 cm in diameter is immersed in oil of density 0.8g/cc. What is the charge on the ball, if it remains just suspended in oil in electric field of intensity 3600 V/M acting in the upward direction?
❎Kripya spam na karein!☺️❎​

Answer 1

● Explaination -

As the copper ball have much higher density than oil, it will get completely immersed in the oil.

Oil displaced is given by -

Volume of oil displaced = Volume of ball

V = 4/3 πR^3

V = 4/3 × π × (0.5)^3

V = 0.5236 cm^3

Mass of oil displaced is calculated by -

M = V × ρ

M = 0.5236 × 0.8

M = 0.4189 g

Therefore, 0.4189 g of oil will be displaced out.

Hope this helps you...

FOLLOW ME

PLZ MARK AS BRAINLIST

☺️☺️❤️❤️

Answer 2

Hey mate here is the correct answer....

Oil displaced is -

Volume of oil displaced = Volume of ball

• Volume(V) = 4/3 πR^(3)

• V = 4/3 × π × (0.5)^(3)

• V = 0.5236 cm^(3)

Mass of oil displaced is.......

• Density(p)= Mass(M)/Volume(V)

• M = V × p

• M = 0.523 × 0.8

• M = 0.4189 gram

Therefore, 0.4189 g of oil will be displaced.

I hope it will be helpful to you....

Please mark me as BRAINLIEST ❤❤❤❤✔✔✔...........