Question

you answer w
A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?
​

Answer 1

Answer:

14.14

Explanation:

Two minutes twenty seconds is 140 seconds

Perimeter of field is 10×4=40

Total time taken to cover distance of one round =40 seconds

Thus,number of rounds =140/40=3.5 rounds

Displacement = diagonal length

Find by Pythagoras theorum

Displacement =

$\sqrt{200}$

= 14.14 m