Question

You are given a solution of 14.8M $NH_{3}$. How many milliliters of this solution do you require to give 100 ml of 1M $NH_{3}$? How much of water will you add?

Answer 1

M1V1=M2V2  

14.8 * V1 = 0.25*100  

V1 = 0.25*100/14.8  

V1 = 1.689ml  

M1V1= M2V2  

14.8*10 = M2*250  

M2 = 14.8*10/250  

M2 = 0.592M