Computer Science, asked by phaddy4128, 9 months ago

You are given an N x N grid of squares. Each square except the top left is filled with a positive integer. You start at the top left corner with a score of 0 and move to the bottom right square by moving either right by one square or down by one square. As you move to the new square, your score becomes [S/2] + k, where S was the score at your previous square and k is the number written in the current square. In the above, [x] is the largest integer which is not greater than x. Thus, [5] is 5, and [5.5] is also 5.
Write a program to find the smallest score with which you can exit the grid.

Answers

Answered by acharyakaveri555
0

Answer:

.

Explanation:

Answered by pratikshahasabe
1

Answer:

#include<stdio.h>

int main()

{

   int n,i,j,sum=0;

   scanf("%d",&n);

   int a[n][n],b[n][n];

   for(i=0;i<n;i++)

   {

       for(j=0;j<n;j++)

       {

           scanf("%d",&a[i][j]);

       }

   }

   for(i=0;i<n;i++)

   {

       for(j=0;j<n;j++)

       {

           b[0][0]=0;

           if(i==0&&j!=0)

           {

               sum=(b[i][j]/2)+a[i][j];

               b[i][j]=sum;

           }

           if(j==0&&i!=0)

           {

               sum=(b[i][j]/2)+a[i][j];

               b[i][j]=sum;

           }

           if(i!=0&&j!=0)

           {

               if(b[i-1][j]>b[i][j-1])

               {

                   sum=(b[i][j-1]/2)+a[i][j];

                   b[i][j]=sum;

               }

               else

               {

                   sum=(b[i-1][j]/2)+a[i][j];

                   b[i][j]=sum;

               }

           }

       }

   }

    printf("%d",b[n-1][n-1]);

    return 0;

}

Explanation:

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