Question

You are given three resistances of 1, 2 and 3 ohms. Shows by diagrams, how with the help of these resistances you can get
(i) 6 Ω
(ii) 611 Ω
(iii) 1.5 Ω; You are given three resistances of 1, 2 and 3 ohms. Shows by diagrams, how with the help of these resistances you can get
(i) 6 Ω
(ii) 611 Ω
(iii) 1.5 Ω

Answer 1

Explanation:

(i) All resistors are to be connected in series as shown below to get a value of 6 Ω:

total resistance, $R = R_1 +R_2 + R_3$

                       = 1  + 2  + 3  

                       = 6 Ώ

(ii) In order to obtain a value of 6/11  all the resistors must be connected in parallel as shown below: if three resistors are connected in parallel, the resulting resistor is given.

 $1/R=1/R_1 +1/R_2 +1/ R_3$

$R_1= 3 \Omega$

$R_2=2\Omega$

$R_3=1\Omega$

$\frac{1}{R} =\frac{1}{3} +\frac{1}{2} +\frac{1}{1}$

$\frac{1}{R} =\frac{2+3+6}{6}$

$\frac{1}{R} =\frac{11}{6}$  

ohms

(iii) To obtain a value of 1.5 Ω, the 1 Ω and 2 Ω resistors should be connected in series and This arrangement should be linked in parallel to the 3 Ω resistor as shown below

Resistance resistors  and  are in series. Hence their net resistance is as follows:

R = R1 + R2

$R = 1 \Omega+ 2 \Omega$

$R = 3\Omega$

This  is connected to another  of resistance in parallel.

Net resistance will therefore be:

$\frac{1}{R} =\frac{1}{R_1} +\frac{1}{R_2}$

$\frac{1}{R} =\frac{1}{3} +\frac{1}{3}$

$\frac{1}{R} =\frac{2}{3}$

$R=\frac{3}{2}$

R=1.5 Ω

You can get all the answers of Chapter 1 in the link below:    

https://brainly.in/question/14961133

   

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Answer 2

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The above answer us correct