You are given two equal resistors. will the total resistance be larger when they are in series or parallel? what will the new resistance be in each case?
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total resistance would be larger in series
let the equal resistances be r ohm
:.in series it would be = r + r =2r
but in parallel it is
1
_____ = r/2
1/r +1/r
let the equal resistances be r ohm
:.in series it would be = r + r =2r
but in parallel it is
1
_____ = r/2
1/r +1/r
Answered by
0
Answer: The series had the larger total resistance.
Explanation:
Adding the total resistances for a circuit in series is Req = R1 + R2. Since you were told the resistors are equal, the Req = 2R.
For two resistors in parallel the equivalent resistance is Req = [(1/R1) + (1/R2)] ^-1 and considered the equal resistors the Req: Req = [2/R] ^-1 = R/2.
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