Question

You are required to make a water bath of 50 kg at 45°C , by mixing hot water at 90°C,with cold water at 20°C. Calculate the amount of hot water required.

plz answer ASAP​

Answer 1

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Here Is Your AnSweR;-

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Heat LosT By Hot water = heat gain by Cold water ;-

$m \times s \: \times heat \: = (50 - m) \times s \times heat$

where S is the specific heat of water

$m \times (90 - 45) = (50 - m) \times s \times heat$

45m = 25( 50-m)

45m + 25m = 1250

m= 17.85 kilograms

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Answer 2

Heat LosT By Hot water = heat gain by Cold water ;-

m \times s \: \times heat \: = (50 - m) \times s \times heatm×s×heat=(50−m)×s×heat

where S is the specific heat of water

m \times (90 - 45) = (50 - m) \times s \times heatm×(90−45)=(50−m)×s×heat

45m = 25( 50-m)

45m + 25m = 1250

m= 17.85 kilograms