You have 3 L of a 5M solution of calcium chloride. How many L would you be able to make of a 0.5M solution?
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M1=moles /volume 1
Moles = M1×vol 1
Moles= M2 × vol2
M1× vol1= M2×Vol2
5×3/0.5=vol2
Vol2=30L
I hope this helps ( ╹▽╹ )
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