You have a 2.0 l balloon filled with air at a temperature of 273 k when the balloon is heated to 323 k, what is the volume ?
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hi there!!!
here is ur answer
according to Charle's law
V=KT
therefore,
V1 /T1 = V2 /T2
T1 =273 K
T2 =323 K
V1 =2.0 L
now ,
V2 = (2.0 L)(323 K)/273 K |
V2 = 2.37 L
hope helped...
here is ur answer
according to Charle's law
V=KT
therefore,
V1 /T1 = V2 /T2
T1 =273 K
T2 =323 K
V1 =2.0 L
now ,
V2 = (2.0 L)(323 K)/273 K |
V2 = 2.37 L
hope helped...
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