Question

you have a sample of granite with density 2.8/cm3. the density of water is 1 g/cm3.what is specific gravity of your granite​

Answer 1

Answer:

2.8.... Becoz specific density is ratio of specific density of substance to the specific density of water at4 degree Celsius. And here is in question water is 1 GM/cm3 at 4degree Celsius

Answer 2

Answer:

The specific gravity of the granite is 2.8

Explanation:

Given :

• Density of the sample granite is 2.8/cm3
• Density of water is 1g/cm3

To find: The specific gravity of the granite

Formula used: $Specific gravity = \frac{Density of an object}{Density of water}$

Solution:

Specific gravity::

Density is defined as the ratio of one material's density to that of another substance used as a reference and Water is standard for both liquids and solids.

$Specific gravity = \frac{Density of an object}{Density of water}$

Density is given as  the ratio of mass to volume or mass per unit volume.

Density = $\frac{mass}{volume}$

$Density = \frac{m}{v}$

Calculating the specific gravity of an object.

Given that,

Density of granite =  2.8 $\frac{g}{cm^{3} }$

Density of water = 1.0 $\frac{g}{cm^{3} }$

$Specific gravity = \frac{Density of an object}{Density of water}$

Specific gravity = $\frac{2.8 g *cm^{3} }{1.0 cm^{3} *g}$

Specific gravity = 2.8

The specific gravity has no unit it is unitless

Final answer:

The specific gravity of the granite is 2.8

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