Question

you have a spinning wheel with 3 green sectors, 2 blue sector and 4 red sector. The probability of getting a green sector and a non blue sector are respectively​

Answer 1

Given :-

• Green sector = 3
• Blue sector = 2
• Red sector = 4

To Find :-

• Probability of getting green sector = ?
• Probability of getting non - blue sector = ?

Solution :-

❒Formula of finding probability :

${\red{\bigstar \: \: {\orange{\underbrace{\orange{\underline{\mathfrak{Probability = \frac{favourable \: outcomes}{total \: outcomes} }}}}}}}}$

❒Than :

${\mapsto{\bf{probability \: of \: getting \: green \: sector }}}$

${\twoheadrightarrow{\sf{Green \: sector = 3}}}$

${\twoheadrightarrow{\sf{Total \: outcomes = 9}}}$

${\leadsto{\sf{Probability = \frac{favourable \: outcomes}{total \: outcomes} }}}$

${\leadsto{\sf{Probability = \frac{3}{9} }}}$

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${\mapsto{\bf{probability \: of \: getting \: non \: blue \: sector }}}$

${\twoheadrightarrow{\sf{non \: blue \: sector = 7}}}$

${\twoheadrightarrow{\sf{Total \: outcomes = 9}}}$

${\leadsto{\sf{Probability = \frac{favourable \: outcomes}{total \: outcomes} }}}$

${\leadsto{\sf{Probability = \frac{7}{9} }}}$

❒So :

${\red{\underline{\green{\underline{\purple{\boxed{\red{\bf{Probability \: of \: getting \: green \: sector = \frac{3}{9} }}}}}}}}}$

${\red{\underline{\green{\underline{\purple{\boxed{\red{\bf{Probability \: of \: getting \: non - blue \: sector = \frac{7}{9} }}}}}}}}}$

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Answer 2

Answer:

$Given :-</p><p>Green sector = 3</p><p>Blue sector = 2</p><p>Red sector = 4</p><p>To Find :-</p><p>Probability of getting green sector = ?</p><p>Probability of getting non - blue sector = ?</p><p>Solution :-</p><p>❒Formula of finding probability :</p><p>{\red{\bigstar \: \: {\orange{\underbrace{\orange{\underline{\mathfrak{Probability = \frac{favourable \: outcomes}{total \: outcomes} }}}}}}}}★ </p><p>Probability= </p><p>totaloutcomes</p><p>favourableoutcomes</p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p>❒Than :</p><p>{\mapsto{\bf{probability \: of \: getting \: green \: sector }}}↦probabilityofgettinggreensector </p><p></p><p>{\twoheadrightarrow{\sf{Green \: sector = 3}}}↠Greensector=3 </p><p></p><p>{\twoheadrightarrow{\sf{Total \: outcomes = 9}}}↠Totaloutcomes=9 </p><p></p><p>{\leadsto{\sf{Probability = \frac{favourable \: outcomes}{total \: outcomes} }}}⇝Probability= </p><p>totaloutcomes</p><p>favourableoutcomes</p><p></p><p></p><p></p><p>{\leadsto{\sf{Probability = \frac{3}{9} }}}⇝Probability= </p><p>9</p><p>3</p><p></p><p></p><p></p><p>▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃ </p><p></p><p>{\mapsto{\bf{probability \: of \: getting \: non \: blue \: sector }}}↦probabilityofgettingnonbluesector </p><p></p><p>{\twoheadrightarrow{\sf{non \: blue \: sector = 7}}}↠nonbluesector=7 </p><p></p><p>{\twoheadrightarrow{\sf{Total \: outcomes = 9}}}↠Totaloutcomes=9 </p><p></p><p>{\leadsto{\sf{Probability = \frac{favourable \: outcomes}{total \: outcomes} }}}⇝Probability= </p><p>totaloutcomes</p><p>favourableoutcomes</p><p></p><p></p><p></p><p>{\leadsto{\sf{Probability = \frac{7}{9} }}}⇝Probability= </p><p>9</p><p>7</p><p></p><p></p><p></p><p>❒So :</p><p>{\red{\underline{\green{\underline{\purple{\boxed{\red{\bf{Probability \: of \: getting \: green \: sector = \frac{3}{9} }}}}}}}}} </p><p>Probabilityofgettinggreensector= </p><p>9</p><p>3</p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p>{\red{\underline{\green{\underline{\purple{\boxed{\red{\bf{Probability \: of \: getting \: non - blue \: sector = \frac{7}{9} }}}}}}}}} </p><p>Probabilityofgettingnon−bluesector= </p><p>9</p><p>7</p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p>▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃$