You have a triangle with 3 ants on different vertices of the triangle. What is the probability that either 2 of the ants or all of the ants collide if all 3 ants start walking on the sides of the triangle?
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Answer:
3 / 4
Step-by-step explanation:
For each ant, there are two choices for which way they walk: either clockwise or anticlockwise.
So there are 2 × 2 × 2 = 2³ = 8 ways for the ants to start walking (e.g. Fred clockwise, Frank clockwise, Frida anticlockwise, is just one of the eight ways).
Only 2 of these result in there being no collision: either all the ants walking clockwise, or all the ants are walking anticlockwise.
So 8 - 2 = 6 ways do resut in a collision.
Therefore,
Pr ( collision ) = 6 / 8 = 3 / 4 = 0.75
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