You have the following routing table. Which of the following networks will not be placed in the neighbor routing table?
R 192.168.30.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0 C 192.168.40.0/24 is directly connected, Serial0 172.16.0.0/24 is subnetted, 1 subnets C 172.16.30.0 is directly connected, Loopback0 R 192.168.20.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0 R 10.0.0.0/8 [120/15] via 192.168.40.1, 00:00:07, Serial0 C 192.168.50.0/24 is directly connected, Ethernet0
A.172.16.30.0
B.192.168.30.0
C.10.0.0.0
D.All of them will be placed in the neighbor routing table
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(^_-)(^_-)(^_-)(^_-)(^_-)(^_-)(^_-)(^_-)(^_-)
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[B]
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[B]
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Answer:
The Correct answer is option C
Explanation:
- In the computer world, any process is described step by step. With limited steps is known as an algorithm.
- IP-Addressing: IP address is the address in the virtual world. Every address on the network has unique identification no. Every data packet holds this unique address to transmit data to the correct destination. Every device has a unique IP address.
- The IP address itself is a separate topic. Currently, we will stick to the routing algorithms. If you want to learn more regarding the IP address, then you can find a lot of material online.
- Routing algorithm: Similarly, the routing algorithm is a step-by-step process that describes how to transfer data over the network.
- Because it has already made 15 hops, the network 10.0.0.0 cannot be added to the routing table of the next router. The route would consist of 16 hops with just one extra, which is not acceptable in RIP networking.
More information about RIP
https://brainly.in/question/11837645?referrer=searchResults
https://brainly.in/question/3452454?referrer=searchResults
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